Friday, May 4, 2018

Ratio and Proportion Problems Shortcut Formulae ExamTricks

Ratio/ Proportion Question Answers Get Shortcut Formulae Ratio, Proportion Questions Check Tricks to Solve Ratio & Proportion Problems
Ratio/ Proportion Problems Shortcut Tricks: Get Fast Solutions for Ratio, Proportion Methods as this portal is dedicated to give Ratio and proportions questions are asked in many exams including competitive exams like IBPS, SSC etc. and also other qualifying exams. These ratio and proportion problems takes a little more time to solve if the candidate does not know the shortcut trick to solve these problems. It is very important for any applicant to learn the shortcut tricks to solve ratio and problems problems if they are preparing for competitive exams to score more marks. More information of Ratio & Proportion Problem regarding shortcut, solutions and how to solve etc is given here......
Details of Ratio, Proportion Problems:
Just go through the same carefully........................
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Basis for ComparisonRatioProportion
MeaningRatio refers to the comparison of two values of the same unit.When two ratios are set equal to each other, it is called as proportion.
What is it?ExpressionEquation
Denoted byColon (:) signDouble Colon (::) or Equal to (=) sign
RepresentsQuantitative relationship between two categories.Quantitative relationship of a category and the total
Keyword'To every''Out of'
The ratio and proportions problems can be solved easily with the applications of the shortcut formulas provided below. Please remember them if you want to solve ratio and proportion questions faster and want to save time in your exams so that you can do more questions and ultimately attempt most questions in your exams,
then you need to learn Shortcut Tricks to solve questions quickly.

Here are some very important ratio and proportion problems shortcuts
If a number x is divided in the ratio a:b ,then
1st part will be=ax/(a+b)
2nd part will be= bx/(a+b)
Or if the number x is divided in three ratios as a:b:c , then
1st part will be=ax/(a+b+c)
2nd part will be=bx/(a+b+c)
3rd part will be= cx/(a+b+c)
The ratio of milk to water in a mixture is A:B . if P liters of water is added to the mixture, then milk to water mixture ratio becomes A:C ,
then the quantity of milk in the mixture is
=AP/(C-B)           liters
And the quantity of water in the mixture is
= BP/(C-B)           liters
If a number x is added to a ratio a:b so that the ratio becomes c:d ,
Then   x= (ad-bc)/(c-d)
If there are two numbers whose sum and difference is a and b respectively,
 then the ratio of those numbers will be = (a+b)/(a-b)
if two quantities A and B are in the ratio a:b ,
then
(A+B):(A-B)::(a+b):(a-b)
If two numbers are given in the ratio a:b and P in both numbers, the ratio becomes c:d ,
Then
1st number = aP(c-d)/(ad-bc)
2nd number = bP(c-d)/(ad-bc)
Sum of numbers = [P(a+b)(c-d)]/(ad-bc)
Difference of numbers = [P(a-b)(c-d)]/(ad-bc)
If the ratio of incomes of two persons is a:b , and also ratio of their expenses is c:d , and each person saves a sum of x rupees,
Then
Income of 1st person  = ax(d-c)/(ad-bc)
Income of 2nd person = bx(d-c)/(ad-bc)
Example:
In a mixture of milk and water, ratio of milk to water is 5:1 . if 5 liters of water is added to the mixture, the ratio becomes 5:2. Determine the quantity of milk in mixture initially?
Solution:
So in the given question, A=5, B=1, C=2, P=5
Now putting the formula as given above
Quantity of milk = AP/(C-B) = (5*5)/(2-1) = 25 liters
So the answer is
25 liters of milk is there in the initial mixture of milk and water.
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